Objectives:
- Atrium design calculation for rectangular grill (IP Unit)
- Atrium design calculation for round grill (IP Unit)
- Atrium design calculation for rectangular grill (SI Unit)
- Atrium design calculation for round grill (SI Unit)
1. Atrium design calculation for rectangular grill (IP Unit)
Routine 4A: Preventing plug holing with rectangular inlets
T˳ = 70˚F
m = 130.3 lb/s
V = 92600 CFM
d = 9.55 ft
Ï’ = 1.0 (See notes 1,2 & 3)
Ks = 0.5 (See note 7)
a = 4 ft
b = 5 ft
N = 4 (No of inlets)
Ar = 0.50 (Suggested value)
Outputs as below:
Ts = 99.1˚F
Vmax = 29840 CFM
Ve = 23150 CFM
Smin = 9.89 ft (See note 6)
Di = 4.44 ft
d / Di = 2.15
Vi = 2315 fpm
Two checks to be done in the end to validate the outputs
- First check: If d/Di is less than 2 that means note 4 condition is not satisfied. As in our case this ratio is greater than 2 that means our note 4 condition is satisfied
- Second check: If Vmax-Ve > 0 that means note 5 condition is satisfied. As in our case Vmax-Ve is greater than 0 that means our note 5 condition is satisfied
2. Atrium design calculation for round grill (IP Unit)
Routine 4B: Preventing plug holing with round inlets
Inputs as below:
Qc = 1400 btu/sT˳ = 70˚F
m = 130.3 lb/s
V = 92600 CFM
d = 9.55 ft
Ï’ = 1.0 (See notes 1,2 & 3)
Ks = 0.5 (See note 7)
Di = 4.75 ft
N = 5 (No of inlets)
Ar = 0.50 (Suggested value)
Outputs as below:
Ts = 99.1˚F
Vmax = 29840 CFM
Ve = 18520 CFM
Smin = 8.85 ft (See note 6)
d / Di = 2.01
Vi = 2090 fpm
Two checks to be done in the end to validate the outputs
- First check: If d/Di is less than 2 that means note 4 condition is not satisfied. As in our case this ratio is greater than 2 that means our note 4 condition is satisfied
- Second check: If Vmax-Ve > 0 that means note 5 condition is satisfied. As in our case Vmax-Ve is greater than 0 that means our note 5 condition is satisfied
3. Atrium design calculation for rectangular grill (SI Unit)
Routine 4A: Preventing plug holing with rectangular inlets
Inputs as below:
Qc = 1500 KWT˳ = 21˚C
m = 45.5 kg/s
V = 43.7 mᶾ/s
d = 3.00 m
Ï’ = 1.0 (See notes 1,2 & 3)
Ks = 0.5 (See note 7)
a = 1.22 m
b = 1.52 m
N = 4 (No of inlets)
Ar = 0.50 (Suggested value)
Outputs as below:
Ts = 37.5 ˚C
Vmax = 15.35 mᶾ/s
Ve = 10.93 mᶾ/s
Smin = 2.98 m (See note 6)
Di = 1.35 m
d / Di = 2.21
Vi = 11.76 m/s
Two checks to be done in the end to validate the outputs
- First check: If d/Di is less than 2 that means note 4 condition is not satisfied. As in our case this ratio is greater than 2 that means our note 4 condition is satisfied
- Second check: If Vmax-Ve > 0 that means note 5 condition is satisfied. As in our case Vmax-Ve is greater than 0 that means our note 5 condition is satisfied
4. Atrium design calculation for round grill (SI Unit)
Routine 4B: Preventing plug holing with round inlets
Inputs as below:
Qc = 1500 KWT˳ = 20˚C
m = 45.5 kg/s
V = 43.7 mᶾ/s
d = 3.00 m
Ï’ = 1.0 (See notes 1,2 & 3)
Ks = 0.5 (See note 7)
Di = 1.45 m
N = 5 (No of inlets)
Ar = 0.50 (Suggested value)
Outputs as below:
Ts = 36.5 ˚C
Vmax = 15.38 mᶾ/s
Ve = 8.74 mᶾ/s
Smin = 2.66 m (See note 6)
d / Di = 2.07
Vi = 10.62 m/s
Two checks to be done in the end to validate the outputs
- First check: If d/Di is less than 2 that means note 4 condition is not satisfied. As in our case this ratio is greater than 2 that means our note 4 condition is satisfied
- Second check: If Vmax-Ve > 0 that means note 5 condition is satisfied. As in our case Vmax-Ve is greater than 0 that means our note 5 condition is satisfied
0 Comments